40 CFR § 1065.644 - Vacuum-decay leak rate.

This section describes how to calculate the leak rate of a vacuum-decay leak verification, which is described in § 1065.345(e). Use the following equation to calculate the leak rate n

leak, and compare it to the criterion specified in § 1065.345(e):

$\begin{array}{c}{\stackrel{·}{n}}_{\mathrm{leak}}=\frac{V_{\mathrm{vac}}}{R}·\frac{\left(\frac{p_2}{T_2}-\frac{p_1}{T_1}\right)}{\left(t_2-t_1\right)}\\ \text{Eq. 1065.644-1}\end{array}$

Where:

Vvac = geometric volume of the vacuum-side of the sampling system.

R = molar gas constant.

p2 = vacuum-side absolute pressure at time t2.

T2 = vacuum-side absolute temperature at time t2.

p1 = vacuum-side absolute pressure at time t1.

T1 = vacuum-side absolute temperature at time t1.

t2 = time at completion of vacuum-decay leak verification test.

t1 = time at start of vacuum-decay leak verification test.

Example:

Vvac = 2.0000 L = 0.00200 m 3

R = 8.314472 J/(mol · K) = 8.314472 (m 2 · kg)/(s 2 · mol · K)

p2 = 50.600 kPa = 50600 Pa = 50600 kg/(m · s 2)

T2 = 293.15 K

p1 = 25.300 kPa = 25300 Pa = 25300 kg/(m · s 2)

T1 = 293.15 K

t2 = 10:57:35 a.m.

t1 = 10:56:25 a.m.

${\stackrel{·}{n}}_{\mathrm{leak}}=\frac{0.0002}{8.314472}·\frac{\left(\frac{50600}{293.15}-\frac{25300}{293.15}\right)}{\left(10:57:35-10:56:25\right)}$

$\begin{array}{c}{\stackrel{·}{n}}_{\mathrm{leak}}=\frac{0.00200}{8.314472}·\frac{86.304}{70}\\ {\stackrel{·}{n}}_{\mathrm{leak}}=0.00030\mathrm{mol}/s\end{array}$

[79 FR 23795, Apr. 28, 2014]